Recap: Existence of Algebraic Closure
Theorem
For every field
Proof (Construction)
Let
Consider the polynomial ring
with one variable
For each
Let
be the ideal generated by these elements.
Claim
If
So there exist finitely many polynomials
Each
Now suppose
Substituting
a contradiction.
Hence
Constructing a Field
Let
Define
Then
Moreover, for each
Thus
Making it Algebraically Closed
If
If not, repeat the process: adjoin roots of polynomials over
If this does not terminate in finitely many steps, take the union
where each
Why is Algebraically Closed
Let
Its coefficients lie in some
By construction,
Hence
Extension of Homomorphisms
Theorem
Let
Let
be a field homomorphism.
Then
such that
Proof
Step 1: Simple Extension
Assume
Define
by applying
Let
Then
Since
Define
This determines a homomorphism
Step 2: General Case (Zorn’s Lemma)
Let
Define a partial order:
Then
By Zorn’s Lemma, there exists a maximal element
If
Since
By Step 1,
Hence
Therefore,
Conclusion
Every field homomorphism
extends to a homomorphism
when