Question 1 — Orthogonal Group is Closed

Define

Here:

  • is the transpose of
  • is the identity matrix

Prove:

is closed in .


Proof

Define:

by

Matrix multiplication and transpose are continuous maps, so:

is continuous.

Then:

Since is closed in and is continuous, the preimage of a closed set is closed.

Therefore:

is closed.


Question 2 — Special Orthogonal Group

Define:

Prove:

is closed in .


Proof

We know:

is closed in .

Also:

Since:

  • determinant is continuous
  • is closed in

we get:

is closed.

Intersection of closed sets is closed, therefore:

is closed.


Question 3 — Closure in and

Let with .

Define:


(a) Closure in

The closure is:


Justification

Every rational number between and is already in .

Also, rationals can approximate and arbitrarily closely.

Thus:

belong to the closure whenever they are rational.

Hence:


(b) Closure in

Now consider as a subset of .

Then:


Justification

Rational numbers are dense in .

Every real number in is a limit of rational numbers in .

Therefore:


Question 4 — Distance to a Set

Let be a metric space.

Let:

be open and

be closed.

Define:

and


(a) Is continuous?


Proof

For any :

and

By triangle inequality:

Taking infimum:

Similarly:

Thus:

Therefore is Lipschitz and hence continuous.


(b) Is continuous?


Proof

Similarly:

Using the same argument:

Thus is Lipschitz and therefore continuous.


Conclusion

Both functions:

are continuous on .